if (x, y)is point of equidistan from the point A( 6, -1 )and B (2,3) show tha x-y=3
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Let the point be P(x, y)
It is equidistant from A and B. Therefore the distance is same
ie, AP = BP
Squaring both sides(to eliminate the square root),
AP² = BP²
(6 - x)² + (-1 - y)² = (2 - x)² + (3 - y)²
36 - 12x + x² + 1 + 2y + y² = 4 - 4x + x² + 9 - 6y
+ y²
37 - 13 - 12x + 4x + 2y + 6y + x² - x² + y² - y² = 0
24 - 8x + 8y = 0
24 = 8x - 8y
24 = 8(x - y)
x - y = 24/8
x - y = 3
Hence proved.
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