Question

if x : y is = $\frac{3}{2}$ then find the value of $\frac{3x+y}{x+3y}$


please help me with this question

Answer 1

Hiii.....friend,

Here is ur answer,

$= > \frac{3x + y}{x + 3y}$

Dividing nr & Dr by y

$= > \frac{ \frac{3x}{y} + 1}{ \frac{x}{y} + 3 }$

Since, x/y = 3/2.

$= > \frac{3( \frac{3}{2}) + 1 }{ \frac{3}{2} + 3}$

=> 11/9

:-) Hope it helps u.