if (x/y)^n-1= (x/y) ^n-3, what is the
value of n ?
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Answer: n = 0
Step-by-step explanation:
(x/y)^n-1 = (x/y)^n-3
When bases are equal, then index or power is equal
∴ n-1 = n-3
∴n-n = -3+1 (transposition)
∴0 = -2
∴ n = 0
Proof: Whenever the index of the a variable is 0, the answer is 1
n^0 = 1
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