Math, asked by sdmm142536, 8 days ago

if (x/y)^n-1= (x/y) ^n-3, what is the
value of n ?​

Answers

Answered by Sreenandan01
1

Answer: n = 0

Step-by-step explanation:

(x/y)^n-1 = (x/y)^n-3

When bases are equal, then index or power is equal

∴ n-1 = n-3

∴n-n = -3+1 (transposition)

∴0 = -2

∴ n = 0

Proof: Whenever the index of the a variable is 0, the answer is 1

n^0 = 1

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