Question

If x + y =p and xy = q then value of 1÷x^2+1÷y^2 is ?
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Answer 1

Step-by-step explanation:

xy=q

on squaring both sides

(xy)^2=q^2...(1)

x+y=p

squaring both sides

(x+y)^2=p^2

x^2+y^2=(x+y)^2-2xy

=p^2-2q...(2)

1/x^2+1/y^2=x^2+y^2/(xy)^2

=p^2-2q/q^2..(from (1) and (2) )