if x +y = root 11 , x^2+y^2 =5 find the value of xy
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x+y=root 11
×^2+y^2=5
(x+y)^2=x^2+y^2+2×x×y
(root 11)^2=5+2xy
11-5=2xy
6/2=xy
3=xy
Therefore, xy=3
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