Question

IF X+Y=ROOT 5 AND X-Y=ROOT 3 FIND THE VALUE OF X^2+Y^2​

Answer 1

$x+y=\sqrt 5\implies (x+y)^2=5 \implies x^2+2xy+y^2=5\\x-y=\sqrt3 \implies (x-y)^2=3 \implies x^2-2xy+y^2=3\\\\x^2+2xy+y^2+x^2-2xy+y^2=5+3\\2x^2+2y^2=8\\\boxed{x^2+y^2=4}$

Answer 2

Answer:

√2 / ( 3√6 - √5 ) = x√3 - ʏ√10

√2 / ( 3√6 - √5 ) × ( 3√6 + √5 ) / ( 3√6 + √5 ) = x√3 - ʏ√10

√2 ( 3√6 - √5 ) / (3√6)² - √5²

( 3√12 - √10 ) / ( 9*6 - 5 )

( 3*2√3 - √10 ) / ( 54 - 5 )

( 6√3 - √10 ) / 49 = x√3 - ʏ√10

ʜᴇɴᴄᴇ, x = 6 / 49 ᴀɴᴅ ʏ = 1 / 49

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs