Question

if (x+y-t)² + ( y+t-x)² + ( t+x-y)² = 0 then find (x+y-t)?​

Answer 1

Step-by-step explanation:

⇒(x2+y2)2=(t−t1)2

⇒x4+y4+2x2y2=t2+t21−2

⇒x4+y4+2x2y2=x4+y4−2      [given]

⇒2x2y2=−2

⇒x2y2=−1

⇒y2=−x21

⇒y2=−x−2

Differentiating w.r.t. x, we get,

⇒2ydxdy=−(−2)x−3

⇒ydxdy=x31