Question

if x * y =
$\sqrt{ {x}^{2} + {y}^{2} }$
then find the value of
$(2 \times 2 \sqrt{3} )$
​

Answer 1

Answer

$\rm{(2*2\sqrt{3})=4}$

Step-by-step explanation

$x\times y=\sqrt{x^2+y^2}$

Question :

$\rm{The~value~of~(2\times2\sqrt{3})?}$

Solution :

$\rm{(2*2\sqrt{3})}$

From the equation, we can know that

x = 2

y = 2√3

$\begin{aligned}\rm{x*y}&\rm{=\sqrt{x^2+y^2}}\\\\\rm{2*2\sqrt{3}}&\rm{=\sqrt{2^2+(2\sqrt{3})^2}}\\\\&\rm{=\sqrt{4+(4\times3)}\\\\&\rm{=\sqrt{4+12}}\\\\&\rm{=\sqrt{16} }\\\\&\rm{=4}\end{aligned}$

Sorry if wrong

Correct me if I'm wrong