if x+y=w+z,then prove that AOB IS A LINE
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{See the figure in the attachment}
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We know that,
Sum of all angles in a circle is equal to 360°.
∠AOC + ∠BOC + ∠DOB + ∠AOD = 360°
» x+y+w+z = 360°
» x+y+x+y = 360° {x+y = w+z)
» 2x+2y = 360°
» 2(x+y) = 360°
» x+y = 180°
x+y = w+z = 180°
As the sum of two adjacent angles is equal to 180° (linear pair), it is a straight line.
Therefore, AOB is a line.
=============================
We know that,
Sum of all angles in a circle is equal to 360°.
∠AOC + ∠BOC + ∠DOB + ∠AOD = 360°
» x+y+w+z = 360°
» x+y+x+y = 360° {x+y = w+z)
» 2x+2y = 360°
» 2(x+y) = 360°
» x+y = 180°
x+y = w+z = 180°
As the sum of two adjacent angles is equal to 180° (linear pair), it is a straight line.
Therefore, AOB is a line.
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☺ Hello mate__ ❤
◾◾here is your answer...
Given: x+y=w+z (1)
To prove: AOB is a line
Proof: x+y+w+z=360° (Sum of all angles around point=360°)
Putting (1) in the above equation, we get
x+y+x+y=360°
⇒2x+2y=360°
⇒x+y=360°/2=180°
Therefore, x and y form a linear pair
Hence, AOB is a straight line.
I hope, this will help you.
Thank you______❤
✿┅═══❁✿ Be Brainly✿❁═══┅✿
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