Question

if √x=y+x find dy/dx​


Solve please

Answer 1

Explanation:

Answer:

1 / 2 √ x - 1

Step-by-step explanation:

Given :

√ x = y + x

Rewrite as :

= > y = √ x - x

Diff. w.r.t. x we get :

= > d y / d x = ( √ x )' - ( x )'

= > d y / d x = 1 / 2 ( 1 / √ x ) - ( x )'

= > d y / d x = 1 / 2 √ x - 1

Hence we required answer!

Answer 2

Answer:

Given : V x = y + x

Rewrite as: => y = v x - x

Diff. w.r.t. x we get :

=> dy/dx= (v x )' - (x )'

=>dy/dx =1/2 (1/ v x) - (x)'

=>dy/dx=1/2 v x -1

Explanation:

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