if x=y^y find dx/ dy
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Answer:
y^(y-1)
Step-by-step explanation:
x=y^y(given)
dx/dy
= x/y (cancelling out d through division)
= y^y/y (placing the value of x)
= y^(y-1) [as we know a^m/a^n = a^(m-n)]
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