Question

If x\y+y\x=1 , Find the value of x^3 +y^3

Answer 1

Answer:

$\frac{x}{y} + \frac{y}{x} = 1$

$x^{2} + y^{2} = xy$

$x^{3} + y^{3} = (x+y)(x^{2} -xy+y^{2})$

But x² + y² - xy

= xy - xy

= 0

Therefore the value of x³+ y³ = 0

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