if x/y+y/ x=-1 find x³-y³
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Step-by-step explanation:
applied =
a3-b3
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4
Step-by-step explanation:
x/y+y/x=-1
x²+y²/xy=-1
x²+y²=-xy
x²+y²+xy=0
x²+xy+y²=0
Then, x³-y³=(x+y)(x²+xy+y²)
x³-y³=(x+y)×0
x³-y³=0
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