If x/y + y/x =-1 then the value of (x 3 - y 3 ) is
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x/y +y/x = -1
⇒x²+y² = -xy
⇒x²+y²+xy =0
now, (x³-y³) = (x-y)(x²+y²+xy)
=0 [∵x²+y²+xy =0]
⇒x²+y² = -xy
⇒x²+y²+xy =0
now, (x³-y³) = (x-y)(x²+y²+xy)
=0 [∵x²+y²+xy =0]
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