If x/y + y/x = -1, then, the value of x³ - y³ is
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If x + y = a and xy = b² , then the value of x³ – x²y - xy² + y³ in terms of a and b is :
(a² + 4b²)a
a³ – 3b²
a³ - 4b²a
a³ + 3b²
Correct Option: C
x3 - x2y - xy2 + y3 = x3 + y3 - x2y - xy2
= (x + y)3 - 3xy(x + y) – xy(x + y)
= (x + y)3 - 4xy(x + y) = a3 - 4b2a
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Step-by-step explanation:
x/y+y/x = -1
now, taking LCM of x and y
(x²+y²)/xy = -1
x²+y² = -xy {transposing xy to RIGHT}
x²+y²+xy=0 ....(Eq-1)
now x³-y³= (x-y)(x²+xy+y²)
so, (x-y)(0) { from (eq - 1)}
therefore, x³-y³= 0
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