if x/y + y/x = -1 then the value of x³-y³ is
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x³ - y³ = (x-y)(x²+xy+y²)..............(i)
Given that,
x/y + y/x = -1
(x²+y²)/xy = -1
x² + y² = - xy
x² + y² + xy = 0
(x²+xy+y²) = 0
Multiply by (x-y) on Both sides
We get,
( x-y )( x²+xy+y² ) = ( x-y )×0
By Equation 1 , We Get,
x³ - y³ = 0
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