Question

if x/y+y/x=1, then the value of x³+y³/x³-y³​

Answer 1

Answer:

Step-by-step explanation:

Answer:

x³-y³=0

Step-by-step explanation:

Given Problem:

If x/y+y/x = -1 then find the value of x³-y³​

Solution:

Given:

x/y+y/x = -1

To Find:

Value of x³-y³

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We know,

⇒x³-y³ =(x-y)(x²+xy+y²)...................(Equation 1)

As Given that in your question,

⇒x/y+y/x= -1

⇒(x²+y²)/xy= -1

⇒x²+y²=-xy

⇒x²+y²+xy= 0

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Now,Multiply by (x-y) on both sides,

⇒(x-y)(x²+xy+y²) = (x-y) × 0

By Equation 1

⇒x³-y³=0

Hence,The value of x³ - y³ = 0

Answer 2

Answer:

Step-by-step explanation:

x/y + y/x = 1

=> x² + y² = xy

=> x² + y² - xy = 0

Now,

x³ + y³ / x³ - y³

= (x + y)(x² - xy + y²) / x³ - y³

= (x + y) * 0 / x³ - y³

= 0.