If x/y+y/x= -1 where x,yis not equal to 0 then the value of (x-y) is
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x/y+y/x= -1 where x,yis not equal to 0 then the value of (x-y) is
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Observing that the pairs (2,3)(2,3) and (3,2)(3,2) are solutions and substituting y = 5 − xy = 5 − x from the second equation into the first one one obtains:
( x² − 5x + 19 )( x − 2 )( x − 3 ) = 0.
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