If x/y + y/x = -1 ( x and y not equal to 0 ), the value of x 3 - y 3
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x/y + y/x = –1
=> x²+y²+xy = 0
x³–y³ = (x–y) (x²+y²+xy) = (x–y) × 0 = 0
=> x²+y²+xy = 0
x³–y³ = (x–y) (x²+y²+xy) = (x–y) × 0 = 0
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