if x/y + y/x = 1 (x,y,≠0), find the value of x³-y³
Answers
Answered by
1
Answer:
x^3 - y^3 = 0
Step-by-step explanation:
If x/y + y/x = 1
simplifies to x^2 + xy + y^2 = 0
as
(x^3 - y^3) = (x - y) ( x^2 + xy + y^2) = 0
HOPE IT HELPS YOU PLEASE MARK ME AS BRAINLIAST AND FOLLOW ME
Similar questions