Question

if x/y + y/x = 1 (x,y,≠0), find the value of x³-y³​

Answer 1

Answer:

x^3 - y^3 = 0

Step-by-step explanation:

If x/y + y/x = 1

simplifies to x^2 + xy + y^2 = 0

as

(x^3 - y^3) = (x - y) ( x^2 + xy + y^2) = 0

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