if x/y + y/x =1, (x,y≠0) , the vale of x³-y³ is?
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Step-by-step explanation:
x/y+y/x=-1
=x²+y²/xy=-1
=x²+y²=-1×xy
=x²+y²=-xy
=x²+y²+xy=0
x³-y³=(x-y)(x²+xy+y²) we got from equation (i) x²+xy+y²=0
=(x-y)(0)
=0
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