Math, asked by Soha25, 2 months ago

If x/y + y/x = -1 (x,y is not equal to 0) , then the value of x³-y³.(please answer this question ASAP)
a. -1
b. 2
c. 1
d. O​

Answers

Answered by rgssaini2511
0

2

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Answered by monsta34
1

Answer:

0

Step-by-step explanation:

 \frac{x}{y}  +  \frac{y}{x}  =  \frac{ {x}^{2}  +  {y}^{2} }{xy}  =  - 1 \\  =  >  {x}^{2}  +  {y}^{2}  =   - xy\\ \\ According \: to \: formula \:   {x}^{3}   -   {y}^{3}  = (x  -  y)( {x}^{2}  + xy +  {y}^{2} ) \\ Putting \:  {x}^{2}  +  {y}^{2}  =  - xy \\ (x + y)(  - xy + xy) \\  = (x + y) \times 0 \\  = 0 \\ Therefore \:  {x}^{3}  -  {y}^{3}  = 0

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