Question

If x/y + y/x = -1 (x,y is not equal to 0) , then the value of x³-y³.(please answer this question ASAP)
a. -1
b. 2
c. 1
d. O​

Answer 1

2

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Answer 2

Answer:

0

Step-by-step explanation:

$\frac{x}{y} + \frac{y}{x} = \frac{ {x}^{2} + {y}^{2} }{xy} = - 1 \\ = > {x}^{2} + {y}^{2} = - xy\\ \\ According \: to \: formula \: {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ Putting \: {x}^{2} + {y}^{2} = - xy \\ (x + y)( - xy + xy) \\ = (x + y) \times 0 \\ = 0 \\ Therefore \: {x}^{3} - {y}^{3} = 0$