Question

if x\y +y\x =-1,(x,y is not equal to zero),then the valye of x^3-y^3​

Answer 1

Answer:

0

Step-by-step explanation:

x/y +y/x=-1

or,x²+y²/ xy=-1

or,x²+y²=-xy

or,x²+xy+y²=0

Now ,

x³-y³=(x-y)(x²+xy+y²)

=(x-y) × 0 [coz, x²+xy+y²=0]

=0