Question

if x/y + y/x =-1 (x,ynot = 0)then the value of Xcube -ycube​

Answer 1

Answer:

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Step-by-step explanation:

We have,

∣

∣

∣

∣

∣

∣

∣

∣

1+x

1

1

1

1+y

1

1

1

1+z

∣

∣

∣

∣

∣

∣

∣

∣

=0

⇒

∣

∣

∣

∣

∣

∣

∣

∣

x

0

1

−y

y

1

0

−z

1+z

∣

∣

∣

∣

∣

∣

∣

∣

=0, use R

1

→R

1

−R

2

and R

2

→R

2

−R

3

Now expand along first row,

⇒x[y(1+z)+z]+y(0+z)=0

⇒xy(1+z)+xz+yz=0

⇒xy+yz+zx=−xyz

⇒x

−1

+y

−1

+z

−1

=−1, divide both sides by xyz

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