Question

if x/y +y/x=6 , find the value of x^3/y^3+y^3/x^3

Answer 1

Answer:

198

Step-by-step explanation:

$(\frac{x}{y} + \frac{y}{x})^{3} = \frac{x^{3} }{y^{3} }+ \frac{y^{3} }{x^{3} }+3(\frac{x}{y}+\frac{y}{x} )$

$6^{3} =$$\frac{x^{3} }{y^{3} }+ \frac{y^{3} }{x^{3} } + 18$

$\frac{x^{3} }{y^{3} }+ \frac{y^{3} }{x^{3} } =198$