if x^y=y^x and y =2x find x
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0
Answer:
Step-by-step explanation:
x
y
=y
x
& x=2y
⇒(2y)
y
=y
2y
⇒2
y
y
y
=(y
y
)
2
⇒2
y
=y
y
⇒
y=2
∴
x=4
⇒
x+y=6
hope it helps
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