Question

if X /Y + Y / x is equal to -1 where x is not equal to zero and Y is not is equal to zero then find the value of x cube minus y cube​

Answer 1

Given

$\frac{X}{Y}+\frac{Y}{X}$= -1

X,y$\neq$0

To find

X³-y³

Solution

$\frac{X}{Y}+\frac{Y}{X}$= -1

$\implies\sf\frac{X^2+Y^2}{XY}$= -1

$\implies\sf\f{X^2+Y^2}={-XY}$

Now Breaking X³-y³

$\boxed{\boxed{\sf\red{X^3-Y^3=(x-y)(x^2+y^2+xy)}}}$

$\sf\red{X^3-Y^3=(x-y)(x^2+y^2+xy)}$

putting the values of x²+y²

$\sf\red{X^3-Y^3=(x-y)(-xy+xy)}$

$\sf\red{X^3-Y^3=(x-y)(0)}$

$\implies\sf\red{X^3-Y^3}=0$

Answer 2

Answer:

_1,1

Step-by-step explanation:

this is the answer of this mcqs