Math, asked by akshataghorpade24, 5 months ago

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if x^y = y^x then dyl dx
1) x(xlogy - y)/y (ylog x - x)
2) y(ylogx - x) / x (x log y-y)
3) y^2(1- log x)/x^2(1-logy)
4)y (1-logx)/x (1-logy)​

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Answered by shabbirstb53
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