Question

if x+y: y +z: Z + x = 5:6:7 then x:y:z =
(A) 3:4:5
(B) 5:6:72
(C) 3:2:40
(D) 1:2:3​

Answer 1

Answer:

Ans: 3:2:4 (None of the above option).

Step-by-step explanation:

lets assume,

x+y=5k ; y+z=6k ; z+x=7k => eq 1,2,3 respectively

add these three equations,

(x+y)+(y+z)+(z+x) = 5k+6k+7k

2(x+y+z) = 18k => x+y+z=9k =>eq 4

Now,

on substituting eq 1 in eq 4

(x+y)+z = 9k => 5k+z=9k =>  z=4k

similarly, x=3k , y=2k

so, x:y:z = 3k:2k:4k = 3:2:4

Hope its helpful.