Question

if x+y,y+z,z+x are in the ratio of 6:7:8and x+y+z=14 then value of x is​

Answer 1

Step-by-step explanation:

let k be constant of proportion

adding first three equations we get

2(x+y+z)=6k+7k+8k

2(x+y+z)=21k

substituting last equation

2*14=21k

k=4/3

so x=4/3*6

=8