Math, asked by anmolagrawal960, 11 months ago

If x+y+z=0 and x^2+y^2+z^2= 12 then find the value of xy+yx+zx?

Answers

Answered by ezza
0

Answer:

Step-by-step explanation:

Use AM-GM inequality.

x^2 + y^2 >(or equal) 2xy

y^2 + z^2 > 2yz

z^2 + x^2 > 2xz

Adding all the equations.

x^2+y^2+z^2-xy-yz-xz >(or equal) 0

Since its given that the equation is equal to zero, we conclude that equation has its minimum value.  

So, all the 3 equations should individually attain their minimum values  

So,

x^2+y^2-2xy=0

(x-y)^2=0

So, x=y

Similarly, y=z and x=z.

So, x=y=z


ezza: mark as brainliest
anmolagrawal960: Hey please tell me solution is right or wrong
ezza: i think its ri8
anmolagrawal960: Please explain me
ezza: ap khud smjhiye aese kese me smjha skti hu
anmolagrawal960: But we have to find the value of xy+yx+zx
ezza: your question is wrong
ezza: its not yx is is yz
anmolagrawal960: No it is yx
Answered by brunoconti
0

Answer:

Step-by-step explanation:

Attachments:

anmolagrawal960: How come please explain me
Sriney: And is -6
anmolagrawal960: How that 12+2 came
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