Math, asked by parent42, 5 months ago

if x+y+z=0 and x^2+y^2+z^2=12 then find the value of xy+yz+zx​

Answers

Answered by Jigs2272
2

Answer:

here ur ans....

Step-by-step explanation:

x^2 + y^2 + z^2 =12 ----------(1)

x + y + z = 0

On squaring both side we get ,

x^2 + y^2 +z^2 + 2xy + 2yz + 2zx = 0

12+2 (xy + yz + zx ) = 0 ( using equation 1)

2 (xy + yz +zx ) = -12

xy+ yz+ zx = -6

| xy + yz + zx | = 6

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