if x+y+z=0 and x^2+y^2+z^2=12 then find the value of xy+yz+zx
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here ur ans....
Step-by-step explanation:
x^2 + y^2 + z^2 =12 ----------(1)
x + y + z = 0
On squaring both side we get ,
x^2 + y^2 +z^2 + 2xy + 2yz + 2zx = 0
12+2 (xy + yz + zx ) = 0 ( using equation 1)
2 (xy + yz +zx ) = -12
xy+ yz+ zx = -6
| xy + yz + zx | = 6
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