if x+y+z=0 and x^2 +y^2+z^2=40, then find xy+ yz+ zx
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Here is how to get the value of xy+yz+zx
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ayushnath01:
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(x+y+z)²=x²+y²+z²+2(xy+yz+xz)
(0)² =40+2(xy+yz+xz)
-40 =2(xy+yz+xz)
-40/2 =xy+yz+xz
xy+yz+xz=-20
(0)² =40+2(xy+yz+xz)
-40 =2(xy+yz+xz)
-40/2 =xy+yz+xz
xy+yz+xz=-20
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