Question

if x+y+z=0, find the value of x³+y³+z³.​

Answer 1

Answer:

if X + Y + Z is equal to zero then the value of x cube+ y cube +Z cube

is equal to 3xyz

Answer 2

Answer:

$x {}^{3} + y {}^{3} + z {}^{3} - 3xyz = (x + y + z)(x {}^{2} + y {}^{2} + z {}^{2} - xy - yz - zx) \\ \\ \\ now(x + y + z) = 0 \\ x {}^{3} + y {}^{3} + z {}^{3} - 3xyz = 0 \\ x {}^{3} + y {}^{3} + z {}^{3} = 3xyz \: \: (answer)$