If x + y + z = 0, find the value of xº + y2 + z3.
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Answer:
x+y+z=0⇒x+y=−z
Cubing on both sides,
(x+y)3=(−z)3
⇒x3+y3+3xy(x+y)=z3
⇒x3+y3+3xy(−z)=−z3
⇒x3+y3−3xyz+z3=0
∴x3+y3+z3=3xyz
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