Question

if x+y+z=0,find x^3+y^3+z^3-3xyz​

Answer 1

Did you mean the question:

If x + y + z = 0, then find x³ + y³ + z³ = ?

                            Or

Prove that x³ + y³ + z³ = 3xyz when x + y + z = 0

If so, Answer:

If x+y+z = 0

We know that x³ + y³ + z³ - 3xyz = (x + y + z)(x² + y² + z² - xy - yz- xz)

We have to substitue the value of x + y + z = 0

x³ + y³ + z³ - 3xyz = (0)(x² + y² + z² - xy - yz- xz)

x³ + y³ + z³ - 3xyz = 0

Take 3xyz to the right side

x³ + y³ + z³ = 3xyz

∴ If x + y + z = 0 then

x³ + y³ + z³ = 3xyz

HOPE THIS HELPS IN ANSWERING YOUR QUESTION... :)

Answer 2

Answer:

0

3xyz-3xyz=0

so the answer is 0

Step-by-step explanation: