Question

If x+y+z=0 show that x^3+y^2+z^3=3xyz​

Answer 1

Answer:

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Answer 2

Answer:

Given:     x+y+z=0⇒x+y=-z⇒(x+y)^3=(-z)^3

⇒x^3+y^3+3xy(x+y)=-z^3

⇒x^3+y^3+3xy(-z)=-z^3

⇒x^3+y^3-3xyz=-z^3

∴z^3+y^3+z^3=3xyz____hence proved.