Question

If x + y - z = 0, Show that x^3 + y^3 - z^3 + 3xy = 0
I want this in hurry
the person who will give answer me first and correct and clear I'll mark. as brainlist​

Answer 1

Answer:

$x + y - z = 0 \\ x + y = z \\ {(x + y)}^{3} = (z) ^{3} \\ {x}^{3} + {y}^{3} + 3 {x}^{2} y + 3x {y}^{2} = {z}^{3} \\ {x}^{3} + {y}^{3} + 3xy(x + y) = {z}^{3} \\ {x}^{3} + {y}^{3} + 3xy(z) = {z}^{3} \\ {x}^{3} + {y}^{3} + 3xy z= {z}^{3} \\ {x}^{3} + {y}^{3} - {z}^{3} + 3xyz = 0$