Question

if x+y+z =0 show that x^3 +y^3+z^3 =3xyz use it to calculate (-27)^3 +(15)^3+(12)3​

Answer 1

Answer:

This is your required answer.

Answer 2

Answer:

14580

Step-by-step explanation:

$a^{3} +b^{3} +c^{3} -3abc = (a+b+c)(a^{2} +b^{2} +c^{2} -ab-bc-ca)\\here (a+b+c) = 0\\Therefore a^{3} +b^{3} +c^{3} -3abc = 0\\a^{3} +b^{3} +c^{3} = 3abc$

$(-27)^{3} +15^{3} +12^{3} =3 * (-4860)\\= -14580$