Question

if X+y+z=0 ,show that x cube+y cube +z cube=3xyz​

Answer 1

Given:- x+y+z=0.

To prove:- x^3+y^3+z^3=3xyz.

Proof:- x+y+z=0. (given)

=> x + y = -z. ..............................(I)

=> (x+y)^3 = (-z)^3.

=> x^3 + y^3 + 3xy(x+y) = -z^3.

=> x^3 + y^3 + z^3 + 3xy(-z) =0. { from eq. (I) }

=> x^3 + y^3 +z^3 - 3xyz =0.

=> x^3 + y^3 + z^3 = 3xyz.

Hence, proved.

Answer 2

Answer:

Kaisa answer diya hai tumne. At least cute to bol dete.