Question

if x+y+z=0 show that x cube + y cube z cube =3xyz​

Answer 1

Step-by-step explanation:

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Answer 2

x3+y3+z3-3xyz= (x+y+z) (X2+y2+z2-xy-yz-zx)

x3+y3+z3-3xyz=0

x3+y3+z3= 3xyz

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