Question

If x + y + z = 0 , show that x cube + y cube + z cube = 3xyz
Please answer me fast its urgent​

Answer 1

Step-by-step explanation:

there is a identity i.e

x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)

x³+y³+z³-3xyz=(0)(x²+y²+z²-xy-yz-zx)

x³+y³+z³-3xyz=0

x³+y³+z³=3xyz

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Answer 2

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