If x+y+z=0,show that x cube +y cube +z cube equal to 3xyz
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Answered by
0
Answer:
When we have formula i.e x cube plus y cube plus z cube minus 3xyz = .......
Step-by-step explanation:
RHS contains X+Y+Z multiplied by other stuff and since x+y+z is zero RHS become zero
Therefore minus 3 xyz goes right side and become positive ..
Hpe u Understand
Answered by
1
Answer:
Step-by-step explanation:
Proof:
x + y + z = 0
Therefore, x + y = -z eqn 1.
Cubing on both the sides we get,
( x + y )^3 =( -z)^3
Therefore, we get,
x^3 + y^3 + 3x^2y + 3x^y = -z^3
Transposing RHS TO lhs,
X^3 + Y^3 + Z^3 = -3xy(x+y)
From eqn1,
x^3 + y^3 + z^3 = -3xy( -z)
Thus, x^3 + y^3 + z^3 = 3xyz
HOPE THIS HELPS YOU...
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