Question

If x + y +z=0, show that x + y +z = 3xyz.
but actually
multime 21.1​

Answer 1

Correct Question :

If (x + y + z) = 0 then,

Show that (x³ + y³ + x³) = 3xyz

AnswEr :

➟ x³ + y³ + c³ - 3xyz = (x + y + z)(x² + y² + z² - xy - yz - zx)

➟ x³ + y³ + c³ - 3xyz = 0 × (x² + y² + z² - xy - yz - zx)

$\blacksquare$ Given that (x + y + z) = 0

➟ x³ + y³ + c³ - 3xyz = 0

➟ x³ + y³ + c³ = 3xyz

$\huge{\red{\ddot{\smile}}}$

Answer 2

Correct Question :

If (x + y + z) = 0 then,

Show that (x³ + y³ + x³) = 3xyz

AnswEr :

➟ x³ + y³ + c³ - 3xyz = (x + y + z)(x² + y² + z² - xy - yz - zx)

➟ x³ + y³ + c³ - 3xyz = 0 × (x² + y² + z² - xy - yz - zx)

■ Given that (x + y + z) = 0

➟ x³ + y³ + c³ - 3xyz = 0

➟ x³ + y³ + c³ = 3xyz