If x+y+z =0, show that x³+y³+z³=3xyz
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Answered by
4
Answer:
Proved
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Answered by
7
Answer:
Given,
x+y+z=0
then,
L. H. S
x3+y3+z3=3xyz
(x+y+z) (x^+y^+z^-xy-yz-zx) +3xyz
0(x^+y^+z^-xy-yz-zx) +3xyz
0+3xyz
3xyz
=L.H.S....
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