Question

if x+y z=0, show that x3+y3+z3=3xyz​

Answer 1

Answer:

if x+y z=0, show that x3+y3+z3=3xyz

Step-by-step explanation:

if x+y z=0, show that x3+y3+z3=3xyz

Answer 2

Answer:

If x+y+z=0, show that x³+y³+z³=3xyz.

solution: We know that

x³+y³+z³-3xyz =(x+y+z) (x²+y²+z²-xy-yz-zx)

putting x+y+z=0,

x³+y³+z³-3xyz=[0](x²+y²+z²-xy-yz-zx)

x³+y³+z³- 3xyz=0

x³+y³+z³= 3xyz

hence proved.