If x+y+z=0 show that x3 , y3 , z3 =3xyz
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Answer:
Given, x3 + y3 + z3 - 3xyz. Therefore, x3 + y3 + z3 - 3xyz =0
Step-by-step explanation:
This means x3 + y3 + z3-3xyz = (x+y+z) (x2+y2+z2-xy-yz-zx).
Now0 ,then.......... x3+y3+z3-3xyz=(0) (x2+y2+z2-xy-yz-zx)....................... [ substituting the value of x+y+z] x3+y3+z3-3xyz=0. x3+y3+z3= 3xyz.
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