Question

If x+y+z =0,show that xcube+ycube+zcub=3xyz​

Answer 1

Answer:

X+y=-z

cube on both sides

(X+y)^3=(-z)^3

x^3+y^3+3xy(X+y)=-z^3

x^3+y^3+3xy ×-z=-z^3

x^3+y^3-3xyz =-z^3

x^3+y^3 +z^3=3xyz