Question

if x+y+z=0 show that (xcube+ycube+zcube)=3xyz​

Answer 1

Answer:

x +y+z=o[given]

xcube+ycube+zcube=3xy

x=o

y=o

z=o

xcube=o

ycube=o

zcube=o

xcube+ycube+zcube-3xyz= 0

o-3xyz=o

=3xyz [if minus number goes other side it will become plus]

Answer 2

Answer:

Hey mate here is your answer.

Step-by-step explanation:

Given-(x+y+z)=0

To prove - (x cube+y cube+z cube)=0

1. identity= x cube+y cube