Question

if x⅓+y⅓+z⅓ =0 then a) X+y+z =0 b)X+y+z=3xyz c) (X+y+z)²=27xyz d)x³+y³+z³=0​

Answer 1

${ \boxed{ \boxed{ \boxed{ \boxed{ \bold \red{x+y+z=3xyz}} }}}}$